Question

The area of a rhombus that has diagonals 30 cm and 40 cm in length is sq.cm

Answer 1

Answer:

25 cm

Step-by-step explanation:

Let ABCD be a rhombus and AC and BD be the diagonals of ABCD. So, AC = 30 cm and BD = 40 cm We know that diagonals of a rhombus bisect each other at right angle. (Perpendicular to each other) So, AO = OC = 15 cm and BO = OD = 20 cm In ∆AOB, by Pythagoras theorem, we have AB2 = AO2 + BO2

= 152 + 202 = 225 + 400 = 625 ⇒ AB = √625 = 25 cm

Since, the sides of rhombus are all equal.

Therefore, AB = BC = CD = AD = 25 cm.

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