Math, asked by palakchughgames, 3 months ago

The area of a rhombus whose diagonal is 10 and 8.2 is ?

Answers

Answered by singmaranushka
1

Answer:

41

Step-by-step explanation:

Answered by Anonymous
0

Answer:

Diagonals of the rhombus = 10 cm and 8 cm,

Area of the rhombus = 10*8/2 = 40 sq cm.

Side of the rhombus = [5^2+4^2]^0.5 = 6.403124237 cm.

Perimeter of the rhombus = 4*6.403124237 = 25.61249695 cm.

Distance between opposite sides = 40/6.403124237 = 6.246950476 cm.

Acute angle of the rhombus = 2*arc tan (4/5) = 77.31961651 deg.

Obtuse angle of the rhombus = 2*arc tan (5/4) = 102.6803835 deg.

Inradius = 6.246950476/2 = 3.123475238 cm.

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