Question

The area of a rhombus whose diagonals are 10 cm and 12 cm is __________.
(120 cm2
, 60 cm2

, 22 cm2
)

Answer 1

Given :

Diagonals of the rhombus are 10 cm and Other diagonal whose measure is 12cm.

To find :

The areaof rhombus.

Solution :

We know that,

Area of Rhombus = 1/2 × D₁ × D₂

= 1/2 × 10 ×12

= 10 × 6

= 60 cm²

Therefore

The area of rhombus is 60 cm²

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More to know :

• Area of Rectangle = L × B

• Area of Square = (Side)2

• Area of Traingle = 1/2 × B × H

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Answer 2

$\large\mathfrak{\pmb{{\underline{Given}}:}}$

• Diagonals of a rhombus are 10cm and 12cm

$\large\mathfrak{\pmb{{\underline{To~find}}:}}$

• The area of the rhombus

$\large\mathfrak{\pmb{{\underline{Solution}}:}}$

• $\sf{Diagonal~1~,~D_{1}={\pmb{10cm}}}$
• $\sf{Diagonal~2~,~D_{2}={\pmb{12cm}}}$

$\sf Area \: of \: a \: rhombus = \frac{1}{2} \times D_{1} \times D_{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = \frac{1}{2} \times 10 \times 12 \: \: \: \: \: \\ \sf = \frac{1}{ \cancel{ \: 2 \: } \: \: ^{1} } \times \cancel{ 120} \: \: \: ^{60} \\ \sf = \blue{ \underline{ \boxed{ \sf{ \pmb{60cm^{2} }}}}} \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\large\therefore\mathfrak{\pmb{{\underline{Required~answer}}:}}$

• Area of the rhombus with diagonals 10cm and 12cm is $\sf{\blue{ \underline{ \underline{ \sf{ \pmb{60cm^{2} }}}}}}$