Question

the area of a rhombus whose digonals are of lengths 10cm and 8.2cm is=​

Answer 1

Step-by-step explanation:

diagonal 1 = 10cm

diagonal 2 = 8.2cm

$area \: of \: rhombus \: = \frac{1}{2} \times d {}^{1} \times d {}^{2} \\ = \frac{1}{2} \times 10 \times 8.2 \\ = 41cm {}^{2}$

Answer 2

Answer:

Step-by-step explanation:

diagonal 1 = 10cm

diagonal 2 = 8.2cm

Area of rhombus = 1/2 * D1 * D2

= 1/2 * 10 * 8.2

= 41 cm^2