Question

the area of a rhombus whose length of the diagonal is 24 cm and 32 cm is ​

Answer 1

Step-by-step explanation:

let the side be x

1.diagonal=24cm

we know 24cm2= x2+x2

576cm=2x2

x2=288

x=17cm so area = 17×17= 289cm2

Answer 2

$\sf\Large{\underline{\underline{Question:-}}}$

Find the area of a rhombus whose length of the diagonal is 24cm and 32 cm each.

$\sf\Large{\underline{\underline{Answer:-}}}$

$\sf\Large{\boxed{Area = 384 cm{}^{2}}}$

Step-by-step explanation:

Formula used:

Area of a rhombus = $\sf\Large\frac{1}{2} \: × \: d_{1} \: ×\: d_{2}$

where $\sf\Large\: d_{1} \: and \: d_{2}$ are the lengths of the two diagonals of a rhombus.

= $\sf\Large\frac{1}{2} \: × \: 24 \: × \: 32$

= $\sf\Large\frac{1}{\cancel{2}} \: × \cancel{24}\: × \: 32$

= $\sf\Large{\boxed{384 \: cm{}^{2}}}$

$\sf\Large\therefore{\boxed{Area = 384 \: cm{}^{2}}}$

$\pink{Hope \: it \: helps}$