Question

The area of a rhombus whose one side measures 6 cm and one diagonal measures 10 cm.

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Answer 1

Given:

Side = 6cm

Diagonal= 10cm

To Find:

Area of rhombus=?

Solution:

Rhombus ABCD

AB= 6cm

BC= 6cm

AC = 10cm

∴In ΔABC,

Perimeter of triangle= AB+BC+AC

                                 = 6+6+10

                                 = 22

Semiperimeter of triangle = 22/2

                                           = 11

Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

                          = $\sqrt{11(11-6)(11-6)(11-10)}$

                          = $\sqrt{11*5*5*1}$

                          = $\sqrt{275}$

                          = 16.583sq.cm

∴Area of rhombus = 16.583*2

                               = 33.166sq.cm

Answer 2

Answer:

33.166sq.cm is the write answer