The area of a right angle triangle is 165 cm square . If the altitude of the triangle exceeds the base by 7 cm, find the base and altitude of the triangle
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Hello mate,
here's your answer:
Let a be the altitude and b be the base.
According to the question,
a=b+7
Area of a right triangle=1/2xbase x altitude
here,165=1/2xbx(b+7)
165=1/2b^2+7/2b
multiplying with 2,
b^2+7b=330
b^2+7b-330=0
by splitting middle term,
b^2+22b-15b-330=0
b(b+22)-15(b+22)=0
(b-15)(b+22)=0
b=15 or -22
length can't be negative. so,
b=15 cm and
a=b+7
=15+7
=22 cm
Therefore base=15cm, altitude=22cm
hope it helps
brainliest pls
❤️bts
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