Question

the area of a right angle triangle is 20cm and one of the side containing the right angle is 4cm the altitude on the hypotenuse
is?​

Answer 1

Answer:

$area \: of \: triangle \: = \frac{1}{2} \times base \times altitude$

$given .\: \: \\ altitude = 4cm \\ and \: area = 20 {cm}^{2}$

$20 = \frac{1}{2} \times base \times 4$

$base = 10cm$

${h}^{2} = {b}^{2} + {p}^{2}$

${h}^{2} = {10}^{2} + {4}^{2}$

${h}^{2} = 100 + 16$

$h = \sqrt{116}$

$h = 10.77cm$

Answer 2

Step-by-step explanation:

• suppose consider a ABC
• AB = 20 cm
• BC = 4cm
• AC =?
• BC²= AC²+AB²
• AC² = AB²-BC²
• = (20)²- (4)²
• =400-16
• = √384
• AC. = 19.5