The area of a right angle triangle is 600sq.cm. If the base of the
triangle exceeds the altitude by 10cm. Find the dimensions of
the triangle. Plz explain in detail.
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Dimensions 30,40,50 cm
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Answer:
let altitude be x cm.
base=x +10
area of triangle=600sq.cm
area of triangle=1/2 *b*h
600=1/2*x*(x+10)
1200=x^2+10x
x^2+10x-1200=0
x^2+40x-30x-1200=0
x(x+40)-30(x+40)=0
(x+40)(x-30)=0
x=-40 is not possible as altitude cannot be -ve
x=30
altitude=30 cm base=40 cm hypotenuse=50 cm
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