The area of a right-angled triangle is 40 cm. If one of its legs measure 8 cm, find the length of other
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Step-by-step explanation:
Let the hypotenuse AC=h and the other two sides be AB=a and BC=b
By Pythagoras theorem, we have h
2
=a
2
+b
2
.....(1)
Given:Area of △ABC=40sq.m
Hence,
2
1
×a×b=40
⇒ab=80 .......(2)
Given perimeter of △ABC=40 cm
That is a+b+h=40
⇒a+b=40–h
Squaring on both the sides, we get
(a+b)
2
=(40−h)
2
⇒a
2
+b
2
+2ab=1600−80h+h
2
⇒h
2
+2(80)=1600−80h+h
2
from (1) and (2)
⇒160=1600−80h
⇒80h=1600–160=1440
∴h=18 cm
Thus the length of hypotenuse is 18 cm.
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