The area of a right-angled triangle is 40 sq cm and its perimeter is 40 cm. The length of its hypotenuse is:
(a) 16 cm
(b) 18 cm
(c) 17 cm
(d) data insufficient
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Given :-
The area of a right-angled triangle is 40 sq cm and its perimeter is 40 cm
To Find :-
Length of hypotenuse
Solution :-
Area of a right-angled triangle = 1/2 × b × h
40 = 1/2 × a × b
40 × 2 = ab
80 = ab (i)
Let the hypotenuse be x
Perimeter = a + b + c
40 = a + b + x
40 - x = a + b
On squaring both sides
(40 - x)² = (a + b)²
As we know,
- (a - b)² = a² - 2ab + b²
- (a + b)² = a² + 2ab + b²
(40)² - 2(40)(x) + (x)² = a² + 2ab + b²
1600 - 80x + x² = a² + 2ab + b²
From 1
1600 - 80x + x² = a² + 2(80) + b²
1600 - 80x + x² = a² + 160 + b²
- a² + b² = x²
1600 - 80x + x² = x² + 160
Cancel x²
1600 - 80x = 160
1600 - 160 = 80x
1440 = 80x
1440/80 = x
18 = x
Option B is correct.
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