Math, asked by Vraj10711, 10 months ago

The area of a right angled triangle is 40 times it’s base. What is it’s height ?

Answers

Answered by Abhis506
0

Step-by-step explanation:

Let the base of the right triangle be 'b' and the height be 'h'.

The area of triangle is given by :-

Area=\frac{1}{2}\times b\times h

Given: The area of a right angled triangle is 40 times its base

⇒ The area of right triangle=40b=\frac{1}{2}\times b\times h

\\\Rightarrow\ 40=\frac{1}{2}h\\\Rightarrow\ h=80

Hence, the height of the right triangle= 80 units

Answered by architasahu
0

Answer:

Base=40cm

Height=80cm

Area=1600cm

Step-by-step explanation:

Base = x

height=?

area=40x (40 times than it's base)

area of right angled triangle=1/2×base×height

40x=1/2×x×h

x=1/2×1/40×x×h

x=80×x×h

2x=80×h

×=80/2

x=40

base = 40(x)

area=1600(40×x)

height=?

area of right angled triangle=1/2×b×h

1600=1/2×40×h

h=1600/20

h=80

hope it helps you

plz mark as brainliest answer

Thank you

Similar questions