Question

The area of a right angled triangle,whose base is 8 cm and hypotenuse is 10 cm,is: (explain in detail)​

Answer 1

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Let the triangle be ABC

Given the base (AB) of a right angled triangle is 8 cm and its hypotenuse (AC) is 10 cm

Using Pythagorean theory,

(AC)² = (AB)² + (BC)²

(10)² = (8)² + (BC)²

100 = 64 + (BC)²

(BC)² = 100 - 64

(BC)² = 36

BC = √36

BC = 6

So, height is 6cm

Area of triangle = 1/2 × base × height

= 1/2 × 8 × 6

= 24

.°. Area = 24cm²

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Answer 2

Answer:

Hey buddy here is your answer

Let the triangle be ABC

Given the base (AB) of a right angled triangle is 8 cm and its hypotenuse (AC) is 10 cm

Using Pythagorean theory,

(AC)² = (AB)² + (BC)²

(10)² = (8)² + (BC)²

100 = 64 + (BC)²

(BC)² = 100 - 64

(BC)² = 36

BC = √36

BC = 6

So, height is 6cm

Area of triangle = 1/2 × base × height

= 1/2 × 8 × 6

=24

since,area=24²cm