Question

The area of a right triangle is 30 sq. m.
Determine its base, if height exceeds the base
by 7 m

Answer 1

$\huge\bold\pink{ANSWER}$

The right angle triangle is that triangle whose one angle is of 90 degree.

Now,

let the base of triangle = x m

So,

the height =( x + 7 )m

Area of right angle triangle =

=1/2 × base × height

=

$1 \div 2 \times (x + 7)x \\ \\ (x + 7)x \div 2 \: = 30 \\ \\ {x}^{2} + 7x = 60 \\ \\ {x}^{2} + 7x - 60 = 0 \\ \\ {x}^{2} + 12x - 5x - 60 = 0 \\ \\ x(x + 12) - 5(x + 12) = 0 \\ \\ (x - 5)(x + 12) = 0 \\ \\ x - 5 = 0 \\ \\ x = 5 \\ \\ x + 12 = 0 \\ \\ x = - 12$

So the base is 5 m .

we have not taken -12 as base because length can't be negative .

So ,

BASE = 5 m

HEIGHT = 5+7 = 12 m

$\underline{Hope\:it\:helps}$

Answer 2

Step-by-step explanation:

ANSWER

The right angle triangle is that triangle whose one angle is of 90 degree.

Now,

let the base of triangle = x m

So,

the height =( x + 7 )m

Area of right angle triangle =

=1/2 × base × height

=

$\begin{lgathered}1 \div 2 \times (x + 7)x \\ \\ (x + 7)x \div 2 \: = 30 \\ \\ {x}^{2} + 7x = 60 \\ \\ {x}^{2} + 7x - 60 = 0 \\ \\ {x}^{2} + 12x - 5x - 60 = 0 \\ \\ x(x + 12) - 5(x + 12) = 0 \\ \\ (x - 5)(x + 12) = 0 \\ \\ x - 5 = 0 \\ \\ x = 5 \\ \\ x + 12 = 0 \\ \\ x = - 12\end{lgathered}$

1÷2×(x+7)x

(x+7)x÷2=30

So the base is 5 m .

we have not taken -12 as base because length can't be negative .

So ,

BASE = 5 m

HEIGHT = 5+7 = 12 m