Question

the area of a right triangle is 600sq.cm.if the base of the triangle exceeds the altitude by 10cm,find the dimensions of the triangle.

Answer 1

Step-by-step explanation:

Let the altitude BC of right-angled triangle ABC be x cm. Then,

Base = BC = (x+10) cm

Area =

2

1

(x+10)x cm

2

2

1

x(x+10)=600

x

2

+10x=1200

x

2

+10x−1200=0

x

2

+40x−30x−1200=0

x(x+40)−30(x+40)=0

(x+40)(x−30)=0

x=30,−40

Hence, Base = 40 cm and Altitude = 30 cm.