Question

the area of a right triangle whose base is 3cm is 6cm2. find the other two sides of the right triangle .

Answer 1

Area of the triangle = 6 cm^2
Base of triangle = 3 cm
Area of triangle = 1/2*base*height
Therefore, 6 = 1/2*3*height
Height = 6*2/3
=12/3
=4 cm
Therefore the height of the right triangle = 4 cm

Now, by applying Pythagoras theorem we can find the hypotenuse,
H^2 = 4^2 + 3^2
H^2 = 16+9
H = root25
H = 5 cm
Therefore hypotenuse of the triangle is 5 cm.

So, the other two sides of right triangle are 4 cm and 5 cm.

Hope this helps you...:)  

Answer 2

Hlo friend.. Cutiepie Here..

Here is ur answer :

Base b of a right triangle = 3 cm

Area of right triangle = 6 cm²

We have to find height.

Let the height be h

A. T. Q

$\frac{1}{2} \times b \times h = 6$


$\frac{1}{2} \times 3 \times h = 6$

$h = \frac{6 \times 2}{3}$

$h = 2 \times 2$


$h = 4 \: cm$


By pythagoras theorem,


${(base)}^{2} + {(height)}^{2} = {(hypotense)}^{2}$


Let the hypotense be c

${3}^{2} + {4}^{2} = c$

$9 + 16 = {c}^{2}$

$25 = {c}^{2}$


$c = \sqrt{25}$

$c = 5$


In a right triangle,

Ist side = 3

IInd side = 4

IIIrd side = 5


HOPE IT HELPS YOU..