Question

the area of a right triangle whose hypotenuse measure 17 cm and one of the other two sides is 8cm​

Answer 1

Answer:

using Pythagoras theorem

hyp²=opp² + adj²

17² =8²+x²

289=64+x²

289-64=x²

225=x²

√225=√x²

x=15

Answer 2

Answer:

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Let ABC be the right triangle in which hyp. AC = 17cm. Then,

BC² = (AC²-AB²)

= (17)²-(8)²=289-64=225.

=> Area of the triangle = (½×BC×AB)cm²

= (½×15×8) cm² = 60 cm².

Step-by-step explanation:

Hope it helps