Question

The area of a right triangle with hypotenuse 26 M and base 24 M

Answer 1

Sol'n: In the right triangle,

(h)² = (p)² + (b)² [ By Pythagoras theorem]

=> (b)² = (h)² – (p)²

=> (b)² = (26)² – (24)²

=> (b)² = 676 – 576

=> (b)² = 100

=> b = √100

=> b = 10

Since, a right triangle is an isosceles.

Let a = 26
b = 24
c = 10

s = (26 + 24 + 10)/2 = 30

Therefore, the area of the triangle

$= \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{30(30 - 26)(30 - 24)(30 - 10)} \\ = \sqrt{30 \times 4 \times 6 \times 20} \\ = \sqrt{14400} \\ = 120$
Hence, the area of the right triangle is 120m².


HOPE IT'LL HELP....:)

Answer 2

$p {}^{2} = h { }^{2} - b {}^{2}$
p2=676-576
p2=100
p=√100
p=10
area of right angle triangle1/2ofb*h
1/2of24*10
=120 sq m.