The area of a rohmbus is 98msquare .If one of its diangal is 14m, find the other diagnal
vakiti:
answer another diagonal is 14
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Area of a Rhombus = 1/2*Product of it's diagonals = 1/2*d1*d2 if d1 and d2 are the two diagonals.
So,
98 = 1/2*14*Length of the other diagonal.
So,
Length of the other diagonal = 14 m
So,
98 = 1/2*14*Length of the other diagonal.
So,
Length of the other diagonal = 14 m
Answered by
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Area=1/2(Product of Diagonal)
d1=14m
d²=x
Area=1/2(d1×d2)
98m²×2=14×x
196/14=x
14m=x
d1=14m
d²=x
Area=1/2(d1×d2)
98m²×2=14×x
196/14=x
14m=x
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