Question

the area of a room is 72m and its length is 9 m 60 cm . what is the breadth of the room

Answer 1

1) Find the perimeter of a rectangle whose length and width are 25 m and 15 m respectively.
Solution : 
Length = l = 25 m and Width = w = 15 m 
∴ P = 2 ( l + w )
⇒ = 2 ( 25 + 15 )
⇒ = 2 x 40 
⇒ = 80 m 
Perimeter = 80 m
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2)How many rectangles can be drawn with 36 cm as the perimeter, given that the sides are positive integers in cm ?
Solution :
Perimeter = 36 
⇒ 2 ( l + w ) = 36
⇒ l + w = 18 
Since length and width are positive integers in centimeters. Therefore, possible dimensions are :
( 1, 17 )cm , ( 2, 16 ) cm , ( 3, 15 ) cm, (4 , 14) cm, ( 5,13) cm, ( 6, 12) cm , ( 7, 11) cm, ( 8, 10 ) cm, ( 9, 9) cm. 
Hence, there are 9 rectangles. 

Answer 2

area = length X breadth

let the breath be back
according to question
72=9.60×b
b=72/9.60
=7.5 m
=7m 500 cm