The area of a sector of a circle bounded by an arc of length 5πcm is equal to 20π sq.cm .Find the radius.
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Let the radius of the circle be r cm and the arc Ab of length 5π cm subtends abgle θ at the centre O of the circle.
Then ,
Arc AB = 5 π cm and Area of sector OAB=20 π sq. cm^2
=====> θ / 360 × 2πr = 5π & θ / 360 × πr^2 = 20 π
=====> θ / 360 × πr^2 / θ / 360 × 2πr^2 = 20π / 5π
=====> r / 2 = 4
===> r = 8 cm
We have Area = 1 / 2 lr ===> 20 π = 1 / 2 × 5 π × r = 8 cm
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