Question

The area of a sector of a circle of radius 5 cm is 5 π cm² . Find the angle contained by the sector.

Answer 1

Answer:

The angle contained by the sector, θ is  72° .

Step-by-step explanation:

Given :  

Area of the sector of a circle, A = 5π cm²

Radius of a circle ,r = 5 cm

Area of the sector of a circle, A = (θ/360) × πr²

5π = (θ/360°) π ×5²

5π =  (θ/360°) × 25π

5π / 25 π =  (θ/360°)  

⅕ =   (θ/360°)

5θ = 360°

θ = 360°/5

θ = 72°

Angle contained by the sector, θ = 72°  

Hence, the angle contained by the sector, θ is  72° .

HOPE THIS ANSWER WILL HELP YOU….

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Answer 2

Hey mate..

Answer :

Area of sector = 5π cm2

Radius = 5cm

5π =

$= \frac{teta \: o}{360degrees} \times \pi \times 25 \\ \\ q = \frac{5\pi \times 360degrees}{25\pi} = 72degrees$

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