Question

The area of a sector of a circle of radius 5cm is 5πcm². Find the angle contained by the sector.

Answer 1

Answer:

Ф=72°

Step-by-step explanation:

area of sector= Ф/360 × πr²=5π

Ф/360 × 5² =5

Ф=360×5/25

Ф=72°

Answer 2

Given :  The area of a sector of a circle of radius 5cm is 5πcm².  

 

To Find : The angle contained by the sector.

 

Solution :  

We have ,Area of the sector of a circle, A = 5π cm² and Radius of a circle ,r = 5 cm

 We know that ,Area of the sector of a circle, A = (θ/360) × πr²

5π = (θ/360°) π ×5²

 5π =  (θ/360°) × 25π

 5π / 25 π =  (θ/360°)  

 ⅕ =   (θ/360°)

 5θ = 360°

 θ = 360°/5

θ = 72°

 Angle contained by the sector, θ = 72°  

 Hence, the angle contained by the sector, θ is  72° .

HOPE THIS ANSWER WILL HELP YOU…

 

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