Question

The area of a sector of a circle of radius 8 cm and central angle 90° is -

Answer 1

(angle/360)×pi×(radius)²=area of sector

answer=50.24

Answer 2

◘ Given ◘

• The radius of a circle, r = 8 cm
• Central angle, θ = 90°

◘ To Find ◘

The area of the sector.

◘ Solution ◘

We know,

$\boxed{\bf{Area\ of\ sector=\frac{\theta}{360^\circ}\times \pi r^2 }}$

Substituting the values :-

$\sf{\longrightarrow Area= \dfrac{90^\circ}{360^\circ} \times \dfrac{22}{7}\times (8)^2}$

$\sf{\longrightarrow Area= \dfrac{1}{40}\times \dfrac{22}{7}\times 64 }$

$\sf{\longrightarrow Area= \dfrac{1}{20}\times \dfrac{11}{7}\times 64 }$

$\sf{\longrightarrow Area= \dfrac{704}{140} }$

$\sf{\longrightarrow Area= 5.028\ cm^2}$

$\bf{\longrightarrow Area= 5.03\ cm^2}$