Question

The area of a sector of a cricle of radius 10.5cm is 69.3cm sq find the centeral angle the sector. ​

Answer 1

Answer:

I hope this helps answer helps you

Answer 2

Answer:

it is the given area of the sector= 69.3 cm sq

and radius= 10.5 cm

π x (10.5)^2 x central angle / 2

360 = 69.3

now area of the sector = πrsq×central angle / 360

Central angle = 69.3 x 360 x 7 / 10.5 x 10.5 x22 = 72 degree

Central angle = 72 degree

hope it helps you ✌️