The area of a sector of radius 6 cm is 13.2 sq cms find the angle which is subtended by the sector at the centre of the circle
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Heya !!!
Radius = 6 cm
Area of sector = 13.2 cm²
πR² theta / 360 = 13.2
22/7 × 6 × 6 × theta = 13.2 × 360
Theta = 13.2 × 360 × 7 / 22 × 6 × 6
Theta = 33264/792
Theta = 42°
Hence,
Angle subtended by sector at the center of the circle is 42°.
★ HOPE IT WILL HELP YOU ★
Radius = 6 cm
Area of sector = 13.2 cm²
πR² theta / 360 = 13.2
22/7 × 6 × 6 × theta = 13.2 × 360
Theta = 13.2 × 360 × 7 / 22 × 6 × 6
Theta = 33264/792
Theta = 42°
Hence,
Angle subtended by sector at the center of the circle is 42°.
★ HOPE IT WILL HELP YOU ★
Answered by
0
area of sector = 13.2
πr²¢/360 = 13.2
¢ =42 degree
hope it helps
mark as brainliest please.
πr²¢/360 = 13.2
¢ =42 degree
hope it helps
mark as brainliest please.
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