The area of a sector, with central angle 150, of a circle is 231sq cm Ifr - what is the circumference (in
cm) of the circle
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Answer:
Given−
AOBisasectorofradius=randthecentralangle=θ.
Tofindout−
theperimeterofthesectorAOB=?
Solution−
ThearclengthAB=
360
o
θ
×2×π×r=
360
o
πθ
×2r.
Nowtheperimeterofthesector=OA+OB+arcAB
=r+r+
360
o
θ
×2πr=2r(
360
o
πθ
+1).
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