Math, asked by richasahu1985bh, 1 day ago

The area of a semicircle is 11088 cm square. its perimeter is​

Answers

Answered by manikandanmanik07
0

heyyyy mate

here is your answer...

given area of semicircle= 11088

T^²/2=11088

T^²=11088×2=22176

r^²=22176×7/22=7056

r^²=7056

r= √7056=84

R=84

now according to question

perimeter of semicircle=2nr/2

2x22/7x84/2=264

answer >>>264

Mark me brainloest

Answered by prachibarapatre
1

Here area of a semicircle is given to be 11088 cm²

We will first find out the radius by using the formula of area of the semicircle

Area = πr² / 2

11088 = 3.14r² / 2

      r² = 7062.4203

       r = 84.038

Perimeter of semicircle = πr + 2r

                                       = 3.14 ( 84.038 ) + 2( 84.038)

                                      = 263.879 + 168.076

                                      = 431.955 cm

Hence, the perimeter of the semicircle will be 431.955 cm

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