Question

the area of a semicircle of diameter 42 cm is​

Answer 1

Answer:

D=42cm

R=D/2

=42/2

=21cm

Area of semicircle = (pi)R^2/2

=1/2×22/7×21×21

=11×3×21

=33×21

=693 cm sq.

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Answer 2

The area of semicircle of diameter 42 cm is 693 cm².

Given:

• A semicircle.
• Diameter (d)=42 cm

To find:

• Area of semicircle.

Solution:

Formula to be used:

1. Area of circle = π r²
2. Area of semicircle = π r²/2
3. Radius (r)= Diameter/2

here r is radius of circle/semicircle.

Step 1:

Find radius of semicircle.

$r = \frac{42}{2}$

or

$\bf r = 21 \: cm$

Step 2:

Find Area of semicircle.

$Area = \frac{22}{7} \times \frac{1}{2} \times 21 \times 21$

cancel common terms

$Area = 11 \times 3 \times 21$

or

$Area = 33 \times 21$

or

$\bf Area = 693 \: {cm}^{2}$

Thus,

Area of semicircle is 693 cm².

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