Question

The area of a sheet of 6237/ 10 sq. cm. If its length is 297 /10 cm , find its width .​

Answer 1

Question:

The area of a sheet of 6237/ 10 sq. cm. If its length is 297 /10 cm , find its width .

Answer:

Area of rectangle = 6237/10 sq.cm

l × b = 6237/10 sq.cm

297/10 × b = 6237/10 sq.cm

b = 6237/10 × 10/297

b = 21 cm

Therefore, width = 21 cm

hope it helps you :-)

Answer 2

Given:-

•Area of a sheet is 6237/10 sq.cm.

•Length of a sheet is 297/10 cm.

To Find:-

•Find its width.

Solution:-

Let consider Breadth of a sheet be x.

we have,

• Length = 297/10 cm
• Area = 6237/10 sq.cm.

Using Formula:

$\: \: \sf \: area \: of \: sheet = length \times breadth$

Now substitute the values,

$\: \: \sf \: \frac{6237}{10} = \frac{297}{10} \times x \\ \\ \: \: \sf \: \frac{ \frac{6237}{10} }{ \frac{297}{10} } = x \\ \\ \: \: \sf \: x = \frac{6237}{1 \cancel0} \times \frac{1 \cancel0}{297} \\ \\ \: \: \sf \: x = 21$

Henceforth,Breadth of a sheet is 21 cm.

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Extra Info...

• Perimeter of rectangle = 2(length + Breadth)
• Length of a rectangle= Area/Breadth
• Breadth of a rectangle= Area/Length
• Diagonal of rectangle = √(Length)^2+(Breadth)^2