Math, asked by dikshadivya75, 9 months ago

The area of a side is 32sq.cm.the area of the other side of the box is 20bsq.cm.if the area of the upper side of the box is 10 sq.cm,then the volume of the box is?

Answers

Answered by viratbibhuti
0

Answer

6400

Step-by-step explanation:

Length= 32 sq

Breadth= 20 bsq

Height = 10 sq.cm

Volume=l×b×h

Volume=32×20×10

Volume = 6400 cm3

Answered by sonalideval056
0

Concept:

The volume of cuboid is l*b*h

Given:

The area of a side is 32sq.cm

The area of the other side of the box is 20bsq.cm

The area of the upper side of the box is 10 sq.cm

To find:

The volume of the box

Solution:

In this question, 3 different sides ae given to us

32, 20, and 10 sq. cm.

So, let one side be l=32 sq. cm

b= 20 sq. com

h= 10sq. cm

We know that we are talking about a cubical box in this question.

And, we know the volume of a cuboid is = l*b*h

So, to find the volume of the box, we will find the volume of the cuboid

v=l*b*h\\v= 32*20*10\\v=6400 cm^{3}

∴ The volume of the given cubical box is 6400cm^{3}

#SPJ2

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