Question

The area of a small plate is 15cm x 15cm and air in column exerts a force of 2250 N on it.How much atmospheric pressure is exerted by air?

Answer 1

Answer:

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Explanation:

Area of head=15cmx15cm

=15/100mx15/100m

=225/10power4

225*10power-4

1 atm=10power5 P

P=Force/ Area

10power5 pa=F/225x10power-4 m

square

F= 10power5 Pa 225x10power-4 m

square

10power5 N/m squarex225x10power-4 m square

* m square will cut will m square

225×10N

F=2250 N

Answer 2

Given,

1. Area of the small plate = 15 cm × 15 cm
2. Force exerted by the air in the column on the plate = 2250 N

To Find,

The atmospheric pressure exerted by the air

Solution,

We have to convert the unit of the area into meters,

Area of the plate = 15 × 15 cm² = 225 cm² = 225 × 10⁻⁴ m² = 0.0225 m²

Now the formula for pressure,

Pressure = $\frac{force}{area}$

⇒ Pressure = $\frac{2250}{0.0225}$ = 100000 = 10⁵ Pa.

Hence, the atmospheric pressure exerted by the air column on the small plate is 10⁵ Pa.