The area of a small rectangular plot is 84sq.m. If the difference between its length and breadth is 5 m,find its perimeter.
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Given ,
Area= lb= 84sq.m, l-b =5m
l-b = 5
Sharing on both sides
(l)^2 + (b)^2 -2(l)(b)= 25
(l)^2 +(b)^2 =25 + 168
(l)^2 +(b)^2 =193
(l+b)^2 -2(l)(b) = 193
(l+b)^2 =361
(l+b) = 19
Perimeter = 2(l+b) =2(19) =38 m.
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Area= lb= 84sq.m, l-b =5m
l-b = 5
Sharing on both sides
(l)^2 + (b)^2 -2(l)(b)= 25
(l)^2 +(b)^2 =25 + 168
(l)^2 +(b)^2 =193
(l+b)^2 -2(l)(b) = 193
(l+b)^2 =361
(l+b) = 19
Perimeter = 2(l+b) =2(19) =38 m.
If u found it useful then please mark it as the brainliest.
Rehan11111:
You have used (a+b)^2 formula......???
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