Math, asked by mannhduzjshaiijdhsuh, 1 year ago

the area of a sqare 1600m2 find the area of a rectangle whose breadth is the same as that of the square and length us 10 cm more than its breadth

Answers

Answered by Ashita1512
1
HOLA MATE HERE IS YOUR ANSWER....

AREA OF SQUARE IS SIDE X SIDE

SIDE X SIDE = 1600

 {s}^{2} = 1600

s = \sqrt{1600}

s = 40 cm

SO , BREADTH OF RECTANGLE IS 50 CM

AND LENGTH IS 50 + 10 = 60 CM

ARE OF RECTANGLE = L × B

= 50 × 60

 = {3000 \: cm}^{2}






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poonam18nov1975: its 1600m2 and 10cm first u should convert to cm . your answer is wrong.
Answered by poonam18nov1975
1

Answer:

160400m²

Step-by-step explanation:

area of square = 1600m2   [given]

but area of square = side*side

therefore, a*a=1600m²   [let a be side of square]

                a²=1600m²  

                 a=√1600m

                 a = 40m

now for area of rectangle,

let its breadth=b

so, its length is 10cm+b     [according to question]

also b=a [breadth of rectangle = side of square]

a=40m   or   a = 4000cm      

so, b=4000cm and l =10+4000=4010

now, area of rectangle = l*b

                                      = 4010cm*4000cm

                                      = 16040000cm²     or    160400m²

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