Question

The area of a sqaure of side 8cm is 1/3 of the area of an rectangle. If the length of the rectangle is double the side of the square find the breadth of the rectangle

Answer 1

Given

The area of a square of side 8cm is 1/3 of the area of an rectangle

To find

Dimensions of the rectangle

Square.

side=8cm

$\boxed{\bf Area \: of \: square =s^2}$

Area of the square =s²=8×8

=64cm²

Rectangle

given

length of the rectangle is double the side of the square

Length=2s=2×8=16cm

let breadth=b

Area of rectangle = 1/3×Area of square

$\boxed{\bf Area \: of \: rectangle =l×b}$

l×b=1/3×64

16×b=64/3

b=4/3 cm

Therefore

breadth of the rectangle =4/3 cm

Answer 2

Solution:

Given:

=> Side of Square = 8 cm

=> Area of Rectangle = 1/3 × Area of square.

=> Length of rectangle is double the side of square.

To find:

=> Breadth of rectangle

Formula used:

=> Area of Square = Side × Side

=> Area of rectangle = Length × Breadth.

Now, first we will find area of square.

=> Area of Square = Side × Side

=> Area of square = 8 × 8

=> Area of square = 64 cm²

Now, we know that length of rectangle is double the side of square,

∴ Length = 16 cm

Now, according to question,

=> Area of Rectangle = 1/3 × Area of square.

=> Length × Breadth = 1/3 × 64

=> 16 × Breadth = 1/3 × 64

=> 16 × Breadth = 21.3

=> Breadth = 21.3/16

=> Breadth = 1.33 cm

∴ Hence, Breadth of rectangle is 1.33 cm.