Question

The area of a square 1600 m find the area of a rectangle whose breadth os same as that of the square and length is 10 m more than its breadth.

Answer 1

Given :

• The area of a square 1600 m².

• The breadth of the rectangle and the side of the square is same.

• The lenght of the is 10 m greater than the side of the square.

To find :

• Area of the rectangle = ?

Step-by-step explanation:

Area of square= 1600 m² [Given]

We know that,

Area of the square = side²

Substituting the values in the above formula, we get,

side² = 1600

side = √1600

side = 40 m

Thus, the side of the square = 40 m

It is given that lenght of the is 10 m greater than the side of the square.

So, the length of rectangle = 40 + 10

The length of rectangle = 50 m

Breadth of the rectangle as same as the side of the square = 40 cm. [Given]

Now,

We know that,

Area of rectangle  = length × breadth

Substituting the values in the above formula, we get,

= 50 × 40

= 2,000.

Therefore, The Area of the rectangle = 2,000 m².

Answer 2

Given:

$\:$

• The area of square = 1600m
• breadth is same as the side of square
• length is 10 m more than its breadth.

To Find:

• The area of rectangle whose breadth is same as that of square.

Solution:

Area of square =A2 side = √1600=40m

breadth =40m length =40+10 =50m

Area of square =areA of rectangle =lxb

Area of square =A2 side

Area of rectangle = Length × breadth

= 40 × 50 m²

= 20,000 m²