Question

The area of a square 1600sq.m.Find the area of a rectangle whose breadth is the same as that of the square and length is 10 m more than its breadth​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Answer:

2000m

Step-by-step explanation:

area of square=1600sq.m

side^2 =1600

side=√1600

side=40m=breadth

length=40+10=50m

area of rectangle =l*b

=40*50

=2000sq. m