The area of a square ABCD is 64 square centimetre find the area of a square obtained by joining the midpoints of the side of the square ABCD
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ABCD is a square. whose area is 64cmsqr
now side sqr = 64
side =8
now in question it's given that we need to join the midpoints of square
therefore the triangle formed will have base and height = 4 cm each
now applying Pythagoras
side of new sqr = √32
area of new square = side sqr = 32 cm sqr
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