Question

the area of a square abcd is 64cmsquare find the area of square obtained by joining the mid points of the sides of square abcd
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Answer 1

Answer :

32 cm^2

Explanation:

ar[ABCD]=64

ar[ABCD]=64s^2=64

64s=8

64s=8's' is length of side of square ABCD

64s=8's' is length of side of square ABCD EFGH is the square

64s=8's' is length of side of square ABCD EFGH is the squareobtained by joining mid pts

64s=8's' is length of side of square ABCD EFGH is the squareobtained by joining mid ptsof ABCD

64s=8's' is length of side of square ABCD EFGH is the squareobtained by joining mid ptsof ABCDside of square EFGH=( 5/2)√2

=5/√2

∴ Area of EFGH=( 5/√2)^2

=s^2/2

=64/2

=32 cm^2

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