Question

The area of a square and a rectangle are in the ratio 2:3. If the side length of the square is the same as the breadth of the rectangle, what is the ratio of the perimeter of the square to the perimeter of the rectangle?

please answer as soon as possible ​

Answer 1

The perimeter of squire is 32 cm

$then \: the \: side \: of \: square \: = \binom{32}{4} = 8cm$

$Then area of square =(8)2=64 cm2$

The ratio of the area of a rectangle to that of a square is 3:2

$then \: area \: of \: rectangle  = \binom{3}{2} \times 64 = 96cm \: (2)$

Let the length of rectangle angle is 3x, and breadth is 2x

Then area of rectangle =3x×2x=96

$= {6}x^{2} = 96 = {x}^{2} = =16⇒x=4 cm$

Then length of rectangle =3×4=12 and breadth =2×4=8 cm

Then perimeter of rectangle =2(12+8)=40

Then difference between the perimeter of the square and the rectangle =40−32=8 cm