the area of a square field is 15129-metre square rani cycles along its boundary at speed of 15km/hr in how much time will she return to the starting point
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26
we know
area of the square = a^2
15129 m2 = a^2
therefore a = sqrt (15129m2)
= 123 m
now perimeter of square = 4a
= 4×123 m
= 492 m
speed of rani = 15km/h
= 15 × 1000 / 3600
= 25/6 m/s
now we know that
speed = distance/time
=> time = distance/speed
= 492 m / 25/6 m/s
= 118.08 s
or 118.0 / 60 minutes
or 1.968 minutes
area of the square = a^2
15129 m2 = a^2
therefore a = sqrt (15129m2)
= 123 m
now perimeter of square = 4a
= 4×123 m
= 492 m
speed of rani = 15km/h
= 15 × 1000 / 3600
= 25/6 m/s
now we know that
speed = distance/time
=> time = distance/speed
= 492 m / 25/6 m/s
= 118.08 s
or 118.0 / 60 minutes
or 1.968 minutes
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7
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