the area of a square field is 1584 Sq meter, find the area of rectanglar field whose perimeter is = to the perimeter of square field and whose length is twice the length
Anshu25601:
Is value of area correct?
Answers
Answered by
3
area of square field=1584
so the length side of field =root 1584=39.8 m
perimeter of square field=4×39.8=159.16 m
lenght of rectangular field=2×39.8=79.6m
perimeter of rectangular field= perimeter of square field
2 (l+b)=159.16
79.6+b=79.58
b=0.02m
so the area of rectangular field =l×b=79.6×0.02=1.592 meter sq.
so the length side of field =root 1584=39.8 m
perimeter of square field=4×39.8=159.16 m
lenght of rectangular field=2×39.8=79.6m
perimeter of rectangular field= perimeter of square field
2 (l+b)=159.16
79.6+b=79.58
b=0.02m
so the area of rectangular field =l×b=79.6×0.02=1.592 meter sq.
Answered by
0
area of square=a^2
a^2=1584
a=√1584
a=39.79 m
length of rectangle = 2×39.8
=79.6m
perimeter of rectangle=perimeter of square
2(l+b)=4a
l+b=4a/2
79.6+b=2×39.79
b=79.58-79.6
b =0.02m
breath=0.02 m
area of rectangle=l×b
=79.6×0.02
=1.592 m^2
a^2=1584
a=√1584
a=39.79 m
length of rectangle = 2×39.8
=79.6m
perimeter of rectangle=perimeter of square
2(l+b)=4a
l+b=4a/2
79.6+b=2×39.79
b=79.58-79.6
b =0.02m
breath=0.02 m
area of rectangle=l×b
=79.6×0.02
=1.592 m^2
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