The area of a square field is 291600m2.a boy cycles along its boundary at 0.91 km/hr.in how much time will he return to the starting point?
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area of square field
=291600 m^2=291.6 km^2
πr2 = 291.6 km^2
r^2 = 291.6 /3.14
r^2 = 92.8
r =9.6 km
distance=circumference of circle= 2πr
=2×3.14 × 9.6 = 60.288 km
given speed = 0.91 km / h
Time = distance / speed
Time = 60.288 / 0.91
Time = 66.2 h = 2days 18.2 h
therefore he will return to the starting point in 2days and 18.2 hours.
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Your Answer : 2days 18 h( approximate )
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=291600 m^2=291.6 km^2
πr2 = 291.6 km^2
r^2 = 291.6 /3.14
r^2 = 92.8
r =9.6 km
distance=circumference of circle= 2πr
=2×3.14 × 9.6 = 60.288 km
given speed = 0.91 km / h
Time = distance / speed
Time = 60.288 / 0.91
Time = 66.2 h = 2days 18.2 h
therefore he will return to the starting point in 2days and 18.2 hours.
______________________________
Your Answer : 2days 18 h( approximate )
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