Question

The area of a square field is 5184 m^2 . Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth .

Answer 1

Answer:

Mark as brainliest

Step-by-step explanation:

Given: area of square =5184m

2

∴ Side of square =

5184

=72m

The perimeter of square =4×72=288m

Let breadth of rectangle =xm

∴ Length of rectangle =2xm

Now, perimeter of rectangle= Perimeter of a square

⇒2(l+b)=288m

⇒2(2x+x)=288

⇒x=

6

288

=48m

∴ Length =2×48=96m, Breadth =48m

Therefore area of rectangle =l×b=96×48=4608m

2

Answer 2

Answer:

Given: area of square = 5184m²

∴ Side of square = √5184 = 72m

The perimeter of square = 4 ×72 = 288m

Let breadth of rectangle = xm

∴ Length of rectangle = 2 xm

Now, perimeter of rectangle

= Perimeter of a square

⇒2(l+b) = 288m

⇒ 2 (2x+x) = 288

⇒x = 228/6 = 48m

∴ Length = 2 × 48 =96m, Breadth = 48m

Therefore area of rectangle

= l×b = 96 × 48 = 4608²

Step-by-step explanation:

Hope it helps,

please mark it as BRAINLIEST!