Math, asked by sharmabasant1961, 6 hours ago

the area of a square field is 5184 m square or rectangular field whose length is twice its breadth and its perimeter is equal to the perimeter of the square field find the area of the rectangle of it​

Answers

Answered by geetanjalis006
1

Step-by-step explanation:

Given: area of square =5184m

2

∴ Side of square =

5184

=72m

The perimeter of square =4×72=288m

Let breadth of rectangle =xm

∴ Length of rectangle =2xm

Now, perimeter of rectangle= Perimeter of a square

⇒2(l+b)=288m

⇒2(2x+x)=288

⇒x=

6

288

=48m

∴ Length =2×48=96m, Breadth =48m

Therefore area of rectangle =l×b=96×48=4608m

2

Therefore, The perimeter of the rectangular feild is 4608m

Answered by harshit19012006
1

Answer:

hi here is your answer:

Step-by-step explanation:

let the one side of square be x

area of square =5184

area = x2

area =√5184

x=72

perimeter of square =perimeter of rectangle given in ques

=)4×72= 284m

perimeter of rectangle = 284 m

let breadth be x

length 2x

=)2(2x+x)=284m

=)3x=142

=)x=44m

breadth =44m

length =2×44=88m

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