Question

The area of a square field is 5184 m2. A rectangular field, whose length is twice its
breadth, has its perimeter equal to the perimeter of the square field. Find the area
the rectangular field .​

Answer 1

Answer:

Hope this will help you

Answer 2

$given \\ area \: of \: a \: square \: field \: = 5184 {m}^{2} \\ {a}^{2} = 5184 \\ a = \sqrt{5184} \\a = 72 \\ also \: given \\ perimeter \: of \: rectangle \: is \: equal \: to \: \\ the \: perimeter \: of \: square \\ perimeter \: of \: square = 4a \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4(72) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 288m \\ so... \\ perimeter \: of \: rectangle \: = 288m \\2( l + b) = 288 \\ l + b = \frac{288}{2} \\ l + b = 144 \\ from \: the \: problem \\ length \: is \: twice \: the \: breadth \\ l = 2b \\ substitute \: l = 2b \: in \: l + b = 144 \\ l + b = 144 \\ 2b + b = 144 \\ 3b = 144 \\ b = \frac{144}{3} \\ b = 48 m\\ so \: length \: of \: rectangle = 2b \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2(48) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 96m \\ now...... \\ area \: of \: rectangle = l \times b \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 96 \times 48 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4608 {m}^{2}$

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