The area of a square field is 5184 m². A rectangular field, whose length is twice its breadth, has its perimeter equal to the perimeter of the square field. Find the area of the rectangular field.
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Answer:
The area of the square field = 5184 sq m.
Each side of the square field = 5184^0.5 = 72 m.
Perimeter of the square field = 4*72 = 288 m.
Perimeter of the rectangular field = 288 m.
Length of the rectangular field is 2B, where B = breadth of the field.
Hence 2(2B+B) = 288, or
3B = 288/2 = 144, or
B = 144/3 = 48 m so length = 2*48 = 96 m.
Area of the rectangular field = 96 * 48 = 4608 sq m.
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Given:
area of square = 5184m
∴ Side of square = √5184 = 72m
The perimeter of square = 4×72 = 288m
Let breadth of rectangle =xm
∴ Length of rectangle =2xm
Now, perimeter of rectangle= Perimeter of a square
⇒2(l+b)=288m
⇒2(2x+x)=288
⇒x = 388/6 =48m
∴ Length =2×48=96m
Breadth = 48 m
Therefore area of rectangle = l x b
=> 96 × 48 = 4608m²
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