Question

The area of a square field is 5184 m². Find the area of a rectangular field, whose perimeter
is equal to the perimeter of the square field and whose length is twice of its breadth.​

Answer 1

Answer:

Area of a rectangular field = 4608 m²

Step-by-step explanation:

Given that :

Area of square = 5184 m²

Let the side of square be a .

a² = 5184 m²

a = √5184 m² = 72 m

We also know that,

Perimeter of rectangle = Perimeter of square

Let the length and breadth of the rectangle be l and b respectively.

A/q

2(l + b) = 4a

l + b = 2a

l + b = 2 × 72 = 144 ______(I)

Also given that,

l = 2b _____(II)

So, From eq. (I) :

2b + b = 144

3b = 144

b = 48

Now in eq. (II) :

l = 2 × 48 = 96

Area of rectangle = lb Sq. Unit

= (96 × 48) m²

= 4608 m²

#Shivam

Answer 2

Answer:

Step-by-step explanation:

Given,

Area of square field = 5184 m².

To Find,

Area of rectangle.

Formula to be used,

Perimeter of square = 4a

Perimeter of rectangle = 2 (l + b)

Solution,

Let the side of square field as a.

Then,

⇒ a² = 5184 m²

⇒ a = √5184 m

⇒ a = 2 × 2 × 2 × 9 = 72 m

Now,

Perimeter of square = 4a

Perimeter of square = 4(72)

Perimeter of square = 288 m

Now,

Perimeter of rectangle = 2 (l + b)

⇒ 288 = 2 (l + b)

As length is twice of its breadth,

⇒ 288 = 2 × (2b + b)

⇒ 288 = 2 × 3b

⇒ 288/2 = 3b

⇒ 144 = 3b

⇒ 144/3 = b

⇒ b = 48

Here, breadth is 48 m.

Now length,

Length = 2 × 48 = 96 m

Now, Area of rectangle  

Area of rectangle = l × b

Area of rectangle = 96 × 48

Area of rectangle = 4608 m².

Hence, the Area of rectangle is 4608 m².