Question

The area of a square field is 5184 m2. Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth.

Answer 1

area=5184
so side=√5184
=72

perimeter of square = 4*72
= 288
For rectangle
breadth= x
length =2x
2x +x= 288
3x=288
x=288/3
x=96 m
length = 2*96
=192
area of rectangle = l*b
= 192*96
= 18432 m2

Answer 2

Here is your solution

Given :-

Area of square = 6889 m^2

we have to find perimeter of square =?

Now

Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

perimeter of square => 4× side .
=> 4×72=288m

Now,

Let,
The breadth of rectangle be x

Then the length be 2x

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2×48) = 96m 

Now,

Area of rectangle = length×breadth

Here,

Area of rectangle =  48×96 

Area of rectangle =4608 m^2

Hopeit helps you