The area of a square field is 5184 metersquare .a rectangle field whose length is twice it's breath has its perimeter equal to the perimeter of the square field find the area of the rectangle
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Let the side of square be (x) m.
area of square = 5184 m^2
![{x}^{2} = 5184 \\ x = \sqrt[2]{5184} \\ x = 72m \\ {x}^{2} = 5184 \\ x = \sqrt[2]{5184} \\ x = 72m \\](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D++%3D+5184+%5C%5C+x+%3D++%5Csqrt%5B2%5D%7B5184%7D++%5C%5C+x+%3D+72m+%5C%5C+)
now according to the question perimeter of square is equal to perimeter of the rectangle. so let the length of rectangle be (l) and breadth be (b).
perimeter of square = perimeter of rectangle

area of square = 5184 m^2
now according to the question perimeter of square is equal to perimeter of the rectangle. so let the length of rectangle be (l) and breadth be (b).
perimeter of square = perimeter of rectangle
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